[알고리즘] 백준 15792 - A/B - 2 (C++)

[문제 링크] : https://www.acmicpc.net/problem/15792

#include<iostream>
using namespace std;

int main(){
    int A, B;
    cin >> A >> B;
    
    cout << A / B << ".";
    A %= B;
    for(int i=0; i<=1000; i++){
        A *= 10;
        cout << A/ B;
        A = A - (A / B) * B;
    }

    return 0;
}